Answer
0.58 A
0.41 A
Work Step by Step
Use Ohm’s law, equation 18–2, and the relationship between peak and rms values, equations 18–8a and 18-8b.
$$I_{peak}= \frac{V_{peak}}{R}$$
$$ =\frac{180V}{310\Omega}=0.58A$$
$$I_{rms}=\frac{ I_{peak}}{\sqrt2}$$
$$ =\frac{180V}{\sqrt2\times310\Omega}=0.41A$$