Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 523: 48

Answer

0.58 A 0.41 A

Work Step by Step

Use Ohm’s law, equation 18–2, and the relationship between peak and rms values, equations 18–8a and 18-8b. $$I_{peak}= \frac{V_{peak}}{R}$$ $$ =\frac{180V}{310\Omega}=0.58A$$ $$I_{rms}=\frac{ I_{peak}}{\sqrt2}$$ $$ =\frac{180V}{\sqrt2\times310\Omega}=0.41A$$
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