Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 522: 38

Answer

$21

Work Step by Step

Multiply the kilowatts of power, by the number of hours, by the cost per kWh. Cost = $\frac{(0.025 kW)(24h)}{day}(365.25days) \frac{\$0.095}{kWh}=\$21$.
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