Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 522: 31

Answer

$1.7\times10^5C$

Work Step by Step

See equation 17-2. The battery’s stored energy equals the charge it delivers multiplied by its voltage. A watt is a joule per second, so a kWh is a unit of energy. $$PE=QV$$ $$Q=\frac{PE}{V}=\frac{(16000 W\cdot hr)(3600s/hr)}{340V}=1.7\times10^5C$$
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