Answer
The new resistance is one-fourth of the original resistance.
Work Step by Step
Use equation 18–3 to find the resistance.
$$R_{original}=\rho\frac{\mathcal{l}}{A}$$
The length of the new wire is half that of the original wire, and the cross-sectional area of the new wire is twice that of the original wire.
$$R_{new}=\rho\frac{0.5\mathcal{l}}{2A}=\frac{1}{4}\rho\frac{\mathcal{l}}{A}=\frac{1}{4}R_{ original }$$