Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 521: 2

Answer

$1.2\times10^{5}C$

Work Step by Step

Use the definition of current, equation 18–1. $$I=\frac{\Delta Q}{\Delta t}$$ $$\Delta Q=I\Delta t=(6.7A)(5.0h)(3600s/h)=1.2\times10^{5}C$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.