Answer
a. 4.76 A
b. 6.59 A
Work Step by Step
a. Assume the voltage drops by 15 percent, i.e., is multiplied by 0.85, and the resistance R stays the same. Using equation 18–2, V=IR, we see that the current also drops by 15 percent.
$$I_f=0.85I_i=0.85(5.60A)=4.76A$$
b. Assume the resistance drops by 15 percent, i.e., is multiplied by 0.85, while the voltage stays at 240 volts. Using equation 18–2, V=IR, we see that the current is divided by 0.85.
$$I_f=\frac{I_i}{0.85}=\frac{5.60A}{0.85}=6.59A$$