Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 521: 10

Answer

$1.3\times10^{21}\frac{e^-}{minute}$

Work Step by Step

Find the current first from equation 18–2, which defines the resistance. $$I=\frac{V}{R}=\frac{4.5V}{1.3\Omega}=3.462A$$ Find the number of electrons per minute from the current. Use the definition of current, equation 18–1. $$I=\frac{\Delta Q}{\Delta t}$$ $$3.462A=\frac{3.462C}{s}\frac{60s}{minute}\frac{1\;e^-}{1.60\times10^{-19}C}=1.3\times10^{21}\frac{e^-}{minute}$$
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