Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - General Problems - Page 524: 90

Answer

$1.4\times10^{12}$ protons.

Work Step by Step

Find the period T, the time for a charge to complete one revolution. $$T=\frac{d}{c}=\frac{6300m}{3.00\times10^8m/s}=2.1\times10^{-5}s$$ In a time T, the charge Q = Ne passes a point in the ring once, and this comprises a current of 11 mA. $$0.011A=\frac{N(1.61\times10^{-19}C)}{ 2.1\times10^{-5}s }$$ $$N=1.4\times10^{12}\;protons $$
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