Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - General Problems - Page 524: 80

Answer

a. 1200 watts b. 100 watts

Work Step by Step

Use equation 18–6b. a. $P=\frac{V^2}{R}=\frac{(120V)^2}{12\Omega}=1200W$ b. $P=\frac{V^2}{R}=\frac{(120V)^2}{140\Omega}=100W$
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