Answer
a) 7.37hp
b) 224km
Work Step by Step
a) $P=\frac{F\Delta x}{\Delta t}=Fv=(440N)(45km/h)(\frac{1000m\cdot1h}{3600s \cdot1km})=5500W$
$5500W\frac{hp}{746W}=7.37hp$
b) $\Delta t=\frac{\Delta PE}{P}=\frac{\Delta QV}{P}$
$\Delta x=v\frac{\Delta QV}{P}=(12.5m/s)\frac{(95A\times3600s)(12V)(24)}{5500W}=2.24\times10^5m=224km$