Answer
$3200 per hour per meter
Work Step by Step
$R=(1.68\times10^{-8}\Omega \cdot m)\frac{1m}{1.96\times10^{-5}m^2}=8.57\times10^{-4}\Omega$
$I=\frac{P}{V}=\frac{15\times10^6W}{120V}=1.25\times10^{5}A$
$P=I^2R=(1.25\times10^5A)^2(8.57\times10^{-4}\Omega)=1.34\times10^4kWh$
$P_{2wires}=2P=2.68\times10^4kWh/m$
$2.68\times10^4kWh/m\times(\$0.12/kWh)=\$3200$ per hour per meter