Answer
9.8 hours.
Work Step by Step
The energy provided by the battery, $Q\Delta V$, is consumed by the lights, their power multiplied by the time.
$$Q\Delta V=Pt$$
Solve for the time.
$$t=\frac{Q\Delta V }{P}=\frac{(75A\cdot h)(3600 s/h)(12\;V)}{92W}=3.52\times10^4s\approx 9.8h$$