Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 17 - Electric Potential - Problems - Page 496: 3

Answer

-1.0 volts. As expected, the final potential is lower than the initial potential to stop the moving electron.

Work Step by Step

Energy is conserved. The change in electrical potential energy is the negative of the change in kinetic energy. The change in electric potential energy is q multiplied by the change in potential. $$\Delta PE=q \Delta V=-\Delta KE$$ The final KE is zero. $$\Delta V=\frac{-\Delta KE}{q}=\frac{KE_i-KE_f}{q}=\frac{mv_i^2}{2q}$$ $$=\frac{(9.11\times 10^{-31}kg)(6.0\times10^5m/s)^2}{2(-1.60\times 10^{-19}C)}$$ $$=-1.0V$$
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