Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 17 - Electric Potential - Problems - Page 496: 20

Answer

$W_{ext}=0.512J$

Work Step by Step

$W_{ext}=q(V_b-V_a)=(qkQ)(\frac{1}{r_{1f}}+\frac{1}{r_{2f}}-\frac{1}{r_{1i}}-\frac{1}{r_{2i}})=(0.50\mu C )\times(8.99\times10^9\frac{N\cdot m^2}{C^2})(35\mu C)(\frac{1}{0.11m}+\frac{1}{0.35m}-\frac{1}{0.23m}-\frac{1}{0.23m})=0.512J$
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