Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 17 - Electric Potential - Problems - Page 496: 2

Answer

$2.72\times 10^{-17}J$ $1.70\times 10^2 eV$

Work Step by Step

Calculate the work done by the electric field using equation 17–2b. $$V_{ba}=-\frac{W_{ba}}{q}$$ $$W_{ba}=-qV_{ba}=-(1.60\times10^{-19}C)(-45V-125V)=2.72\times 10^{-17}J$$ Multiply by $\frac{1eV}{1.60\times 10^{-19}J}$ to find the answer in electron volts, $1.70\times 10^2 eV$.
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