Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 17 - Electric Potential - Problems - Page 496: 19

Answer

2.8 nC.

Work Step by Step

Use equation 17–5, which gives the potential V of a point charge. $$V=165volts=\frac{1}{4\pi\epsilon_o}\frac{Q}{r}$$ $$Q=4\pi\epsilon_orV$$ $$=(\frac{C^2}{8.99\times10^9 N\cdot m^2})(0.15m)(165V)$$ $$=2.8\times10^{-9}C$$
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