Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 17 - Electric Potential - Problems - Page 496: 18

Answer

$1.80\times10^5V$.

Work Step by Step

Use equation 17–5 to find the potential of a point charge. $$V=\frac{1}{4\pi\epsilon_o}\frac{Q}{r}$$ $$V=(8.99\times10^9\frac{N\cdot m^2}{C^2})\frac{3.00\times10^{-6}C}{1.50\times10^{-1}m}$$ $$=1.80\times10^5V$$
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