Answer
$3.7\times10^{-10}C$
Work Step by Step
Use the definition of capacitance with equation 17–9 for the capacitance of a parallel-plate capacitor with a dielectric.
$$Q=CV=\kappa\epsilon_o \frac{A}{d}V $$
$$=(3.7)(8.85\times10^{-12}C^2/(N\cdot m^2)) \frac{\pi(0.0055m)^2}{0.00010m}(12V) $$
$$=3.7\times10^{-10}C$$