Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 17 - Electric Potential - General Problems - Page 499: 83

Answer

$3.7\times10^{-10}C$

Work Step by Step

Use the definition of capacitance with equation 17–9 for the capacitance of a parallel-plate capacitor with a dielectric. $$Q=CV=\kappa\epsilon_o \frac{A}{d}V $$ $$=(3.7)(8.85\times10^{-12}C^2/(N\cdot m^2)) \frac{\pi(0.0055m)^2}{0.00010m}(12V) $$ $$=3.7\times10^{-10}C$$
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