Answer
$8.3\times10^{-10}C$
Work Step by Step
This situation is covered by equation 16–10. The separation distance is a red herring.
$$E=\frac{Q/A}{\epsilon_o}$$
$$Q=\epsilon_oEA$$
$$=(8.85\times10^{-12}C^2/(N \cdot m^2))(130N/C)(0.85m)^2$$
$$=8.3\times10^{-10}C$$