Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 15 - The Laws of Thermodynamics - Problems - Page 440: 40

Answer

$1.3\times10^3J/K$

Work Step by Step

$$\Delta S=\frac{Q}{T}=\frac{mc\Delta T}{T}$$ Use the average temperature in the calculation. $$=\frac{(1.0kg)(4186 J/(kg \cdot C^{\circ}))(100C^{\circ})}{(50+273)K}$$ $$=1.3\times10^3J/K$$
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