Answer
$1.3\times10^3J/K$
Work Step by Step
$$\Delta S=\frac{Q}{T}=\frac{mc\Delta T}{T}$$
Use the average temperature in the calculation.
$$=\frac{(1.0kg)(4186 J/(kg \cdot C^{\circ}))(100C^{\circ})}{(50+273)K}$$
$$=1.3\times10^3J/K$$
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