Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 15 - The Laws of Thermodynamics - Problems - Page 439: 13

Answer

a) $\Delta U_{ac}=-84J$ b) $W_{dc}=28J$ c) $Q_{cda}=-112J$ d) $U_{ac}=-140J$ e) $Q_{da}=-156J$

Work Step by Step

a) $\Delta U_{ac}=Q_{ac}-W_{ac}=-175J-(-35J)=-140J$ $Q_{abc}=\Delta U_{abc}+W_{abc}=-140J+56J=-84J$ b) $W_{bc}=0$ $W_{cda}=W_{cd}=P_c\Delta V_{cd}=P_c(V_c-V_d)$ $P_c(V_d-V_c)=-\frac{1}{2}P_b(V_a-V_b)=-\frac{1}{2}W_{abc}=-\frac{1}{2}(-56)=28J$ c) $Q_{cda}=\Delta U_{cda}+W_{cda}=-140J+28J=-112J$ d) $U_a-U_c=U_{ac}=-140J$ e) $U_d=U_c+12J$ $U_{da}=U_a-U_c-12J=\Delta U_{ac}-12J=-156J$ $Q_{da}=U_{da}+W_{da}=-156J$
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