Answer
a) See line A in image
b) $W=2550J$
$\Delta U=3825J$
c)See curve and line B in image
d) $\Delta U=3825J$
Work Step by Step
a) See line A in image
b) $W=P\Delta V=(425\frac{N}{m^2})(6.00m^3)=2550J$
$\Delta U=\frac{3}{2}nR\Delta T=\frac{3}{2}(PV_1-PV_2)=3825J$
c)See curve and line B in image
d) The change in internal energy for isothermal reaction is 0
$\Delta U$is only dependent on $\Delta T$, so it is the same as b) 2.
$\Delta U=3825J$