Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 15 - The Laws of Thermodynamics - Problems - Page 438: 7

Answer

a. Q = 0 b. 2630 J c. The temperature rises

Work Step by Step

a. The process is adiabatic, so Q=0. b. Calculate the change in internal energy from $\Delta U=Q-W$ $$\Delta U = 0-(-2630J)=2630J $$ c. Internal energy is proportional to temperature, so the temperature rises.
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