Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 15 - The Laws of Thermodynamics - General Problems - Page 442: 75

Answer

$4.6\times10^6J$ of heat in half an hour.

Work Step by Step

Table 15–2 shows that riding a bicycle at a racing pace requires 1270 watts. According to the problem, that power, exerted for half an hour, is the work input to the heat pump. $$W=1270\frac{J}{s}(1800s)$$ $COP=\frac{Q_H}{W}$ $$Q_H=W(COP)=(1270watts)(1800s)(2.0)=4.6\times 10^6J$$
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