Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 15 - The Laws of Thermodynamics - General Problems - Page 441: 68

Answer

a. $P_A(V_C-V_A)$. b. $P_C(V_C-V_A)$. c. $\frac{1}{2}(P_A+P_C)(V_C-V_A)$.

Work Step by Step

The work done is the area under the PV curve that represents the process. As the process goes from state A to state B, or from state D to state C, there is no work done, because there is no volume change. The PV diagram is provided with the problem. a. $W_{ADC}=W_{AD}+0=P_A(V_C-V_A)$ b. $W_{ABC}=0+W_{BC}=P_C(V_C-V_A)$ c. To find this area, use the formula for a trapezoid. $W_{AC}=\frac{1}{2}(P_A+P_C)(V_C-V_A)$
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