Answer
See answers.
Work Step by Step
a. The work is done at constant pressure. Use equation 15–3.
$$W=P\Delta V$$
$$(1.01\times10^5 Pa)(4.1m^3-1.9m^3)=2.2\times10^5 J$$
b. Apply the first law of thermodynamics.
$$\Delta U=Q-W=5.80\times10^5J-2.22\times10^5 J=3.6\times10^5 J$$
c. See diagram.