Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 15 - The Laws of Thermodynamics - General Problems - Page 441: 57

Answer

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Work Step by Step

a. The work is done at constant pressure. Use equation 15–3. $$W=P\Delta V$$ $$(1.01\times10^5 Pa)(4.1m^3-1.9m^3)=2.2\times10^5 J$$ b. Apply the first law of thermodynamics. $$\Delta U=Q-W=5.80\times10^5J-2.22\times10^5 J=3.6\times10^5 J$$ c. See diagram.
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