Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 14 - Heat - Problems - Page 410: 42

Answer

5.0$^\circ$ Celsius

Work Step by Step

Calculate the rate of heat flow using equation 14–5. $$\frac{Q}{t}=kA\frac{T_1-T_2}{\mathcal{l}}$$ $$95W=(\frac{0.84J}{s \cdot m \cdot C^{\circ}})(4\pi(0.03m)^2)\frac{\Delta T}{0.00050m}$$ Solve for a temperature difference of 5.0 Celsius degrees.
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