Answer
93 W
Work Step by Step
Calculate the rate of heat flow using equation 14–5.
$$\frac{Q}{t}=kA\frac{T_1-T_2}{\mathcal{l}}$$
$$=(\frac{380 J}{s \cdot m \cdot C^{\circ}})(\pi (0.01m)^2)\frac{460^{\circ}C-(22^{\circ}C)}{0.56m}$$
$$=93W$$
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