Answer
$7.1\times10^6J$
Work Step by Step
The silver must first be heated to the melting temperature, and then liquified.
$$Q=Q_{heat}+Q_{melt}$$
$$Q=mc\Delta T+mL$$
$$Q=(23.50kg)(\frac{230J}{kg\cdot C^{\circ}})(961^{\circ}C-25^{\circ}C)+(23.50kg)(0.88\times10^5J/kg)$$
$$Q=7.1\times10^6J$$