Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 14 - Heat - Problems - Page 408: 5

Answer

$1~Btu = 0.252~kcal = 1056~J$

Work Step by Step

$1~Btu = (1~lb)(1^{\circ}F)$ $1~Btu = (1~lb)(\frac{454~g}{1~lb})(1^{\circ}F)(\frac{5^{\circ}C}{9^{\circ}F})$ $1~Btu = 252.2~g~^{\circ}C$ $1~Btu = 252~cal$ $1~Btu = 0.252~kcal$ We then convert from units of kcal to joules; $1~Btu = (0.2522~kcal)(\frac{4186~J}{1~kcal})$ $1~Btu = 1056~J$
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