Answer
$1.1\times 10^7J$
Work Step by Step
A kilocalorie raises the temperature of 1 kg of water by 1 degree Celsius.
$$(34.0kg) (\frac{4186J}{1kcal})\frac{1kcal}{(1kg) 1C^{\circ}}(95C^{\circ}-15^{\circ}) \approx1.1\times 10^7J$$
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