Answer
$4\times10^{15}J$
Work Step by Step
Use equation 14–2.
$$Q=mc\Delta T=\rho Vc\Delta T $$
$$Q=(1000kg/m^3)(1000m)^3 (\frac{4186J}{kg\cdot C^{\circ}})(1C^{\circ})$$
$$=4\times10^{15}J$$
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