# Chapter 13 - Temperature and Kinetic Theory - Problems: 4

A high of $57.8^{\circ} C$ and a low of $-89.4^{\circ} C$.

#### Work Step by Step

Use the formulas on page 362. $$\frac{5}{9}(136^{\circ} F – 32) = 57.8^{\circ} C$$ $$\frac{5}{9}(-129^{\circ} F – 32) = -89.4^{\circ} C$$

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