Answer
$v_{rms}=260\;\rm m/s$
$P= 3.68\times10^{-22}\;\rm atm$
Work Step by Step
We know that rms speed (Root Meas Square speed) is given by
$$v_{rms}=\sqrt{\dfrac{3kT}{m}}$$
whereas $k$ is the Boltzmann constant, $T$ is the temperature of the Hydrogen, and $m$ is the mass of the Hydrogen atom.
Plugging the given;
$$v_{rms}=\sqrt{\dfrac{3\cdot 1.38\times 10^{-23}\cdot 2.7}{1.66\times10^{-27}}}$$
$$\boxed{v_{rms}\approx \bf260\;\rm m/s}$$
Now we need to find the pressure.
We can assume that the gas in outer space is an ideal gas, so we can use the ideal gas law.
$$PV=NkT$$
$$P=\dfrac{NkT}{V} =\dfrac{1\cdot 1.38\times 10^{-23}\cdot 2.7}{1\times 10^{-6}}$$
$$P= 3.73\times 10^{-17}\;\rm N/m^2$$
Now we need to convert to atm.
$$P=\rm 3.73\times 10^{-17}\;\rm N/m^2\cdot \dfrac{1\;atm}{1.013\times10^5\;N/m^2}$$
$$\boxed{P=\bf3.68\times10^{-22}\;\rm atm}$$