Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 13 - Temperature and Kinetic Theory - General Problems - Page 388: 82

Answer

0.11 degrees C

Work Step by Step

The change in the length is to be less than 1.0 micrometers. $$\Delta \mathcal{l}=\alpha \mathcal{l}_o \Delta T \lt1.0\times 10^{-6}m$$ $$\Delta T \leq \frac{1.0\times 10^{-6}m }{(9\times 10^{-6}/C^{\circ})(1.0m)} = 0.11 C^{\circ}$$
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