Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Problems - Page 355: 46

Answer

$\pm0.50Hz$

Work Step by Step

The beat period T is 2.0 seconds, so the beat frequency is 1/T, or 0.50 Hz. The other string differs in frequency from 350Hz by $\pm0.50Hz$. The tuner doesn’t know whether the second string’s frequency is higher or lower than that of the first string.
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