Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Problems - Page 355: 37

Answer

a. 0.585 m b. 858 Hz

Work Step by Step

See figure 12-11. For a pipe open at both ends, the fundamental frequency is $f_1=\frac{v}{2 \mathcal{l}}$. a. At that temperature, the speed of sound is 344.2 m/s, using the formula on page 329. $$\mathcal{l}=\frac{v}{2f_1}=\frac{344.2m/s}{2(294Hz)}=0.585m $$ b. Look up the speed of sound in helium in Table 12–1: it is 1005 m/s. Find the pipe’s fundamental frequency. $$f_1=\frac{1005 m/s}{2 (0.58537m)}=858.4Hz \approx 858 Hz$$
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