Answer
See answers.
Work Step by Step
a. See figure 12-11. For a pipe open at both ends, the fundamental frequency is $f_1=\frac{v}{2 \mathcal{l}}$. Solve for the length.
$$\mathcal{l}=\frac{v}{2f_1}$$
The length is calculated as follows, using the speed of sound as a function of temperature that is the first equation in Chapter 12.
$$\mathcal{l}=\frac{331+(0.60)(18)\;m/s}{2(262Hz)}=0.652\;m$$
b. The frequency of the standing wave in the tube is the same, 262 Hz. The wavelength of the fundamental is twice the length of the pipe, or 1.30 m.
c. The wavelength and frequency of the traveling sound wave are the same as that of the standing wave inside the pipe, because air is the medium inside the organ pipe. The frequency of the sound wave is 262 Hz. The wavelength of the sound wave is 1.30 m.