Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Problems - Page 355: 25

Answer

10 octaves.

Work Step by Step

Going up 1 octave means doubling the frequency. Find the number of octaves, n, between the 2 frequencies. $$20000 Hz = 2^n(20Hz)$$ $$1000=2^n$$ $$n=\frac{log1000}{log2}=9.97\approx 10$$
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