Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Problems - Page 354: 6

Answer

300 m

Work Step by Step

The distance traveled is the same, and equals vt. The sound travels faster in concrete and takes less time. The speed of sound in concrete is given to one significant figure in Table 12-1. $$D=v_{concrete}t_{concrete}=v_{air}t_{air}$$ $$(3000m/s)(t_{air}-0.80s)= (343m/s)(t_{air})$$ Solve for the time the sound traveled in air. $$t_{air}=\frac{3000m/s}{3000m/s-343m/s}(0.80s)$$ The desired distance D is $v_{air}=343m/s$ multiplied by that. Putting in numbers, $D \approx 300m$.
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