Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 11 - Oscillations and Waves - Problems - Page 325: 59

Answer

$24^{\circ}$.

Work Step by Step

The angle of refraction can be found from the law of refraction, which is equation 11–20. The speeds of the incoming and outgoing sound waves can be found from the equation given in the problem. $$\frac{sin\theta_2}{ sin\theta_1}=\frac{v_2}{v_1}=\frac{331+0.60T_2}{331+0.60T_1}$$ $$ sin\theta_2= sin25^{\circ}\frac{331+0.60(-15)}{331+0.60(15)}=0.4002$$ $$ \theta_2= sin25^{-1}0.4002\approx 24^{\circ}$$
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