Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 11 - Oscillations and Waves - Problems - Page 324: 27

Answer

3.0 s

Work Step by Step

The period of a pendulum is given by $T=2 \pi \sqrt{\frac{\mathcal{l}}{g}}$. The lengths are the same. $$\frac{T_{M}}{T_{E}}=\sqrt{\frac{g_E}{g_M}}$$ $$T_M=T_E\sqrt{\frac{g_E}{g_M}}=(1.85s)\sqrt{\frac{1}{0.37}}\approx 3.0 s$$
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