Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 11 - Oscillations and Waves - Problems - Page 323: 24

Answer

$f=\frac{1}{2\pi}\sqrt{\frac{2k}{m}}$.

Work Step by Step

This is a mass on a spring, with an effective spring constant of 2k. We can then calculate the frequency of vibration. $$f=\frac{1}{2\pi}\sqrt{\frac{k_{effective}}{m}}=\frac{1}{2\pi}\sqrt{\frac{2k}{m}}$$
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