Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 11 - Oscillations and Waves - General Problems - Page 326: 83

Answer

230 Hz.

Work Step by Step

Find the linear velocity of the ripples: $v=\omega r$. $$v=(33.333\frac{rev}{60s})(\frac{2 \pi rad}{rev})(0.102\;m)=0.3560\;m/s$$ This is the speed of the “waves” moving past the needle. Find the frequency of the waves. $$f=\frac{v}{\lambda}=\frac{0.3560\;m/s }{0.00155\;m}\approx 230\;Hz$$
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