Answer
$2.6 \times 10^{13}Hz$
Work Step by Step
The spring constant of the bond stays the same.
Use equation 11-6b to relate frequency, mass, and spring constant.
$$f=\frac{1}{2 \pi}\sqrt{\frac{k}{m}}$$
$$k=4 \pi^2f^2m $$
$$ (3.7 \times 10^{13}Hz)^2(16amu) = (f)^2(32amu)$$
Solve for f = $2.6 \times 10^{13}Hz$.