Answer
$1\times 10^4Pa$
Work Step by Step
We can find the required pressure as
$\Delta P=\rho g\Delta h$
We plug in the known values to obtain:
$\Delta P=(1.05\times 10^3)(9.81)(1)$
$\Delta P=1.029\times 10^4Pa=1\times 10^4Pa$
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