Answer
$8.3\times 10^{-6}Kg$
Work Step by Step
We can find the required mass as follows:
$m=\frac{12\pi r\gamma}{g}$
We plug in the known values to obtain:
$m=\frac{12\pi(3\times 10^{-5})(0.72)}{9.81}$
$m=8.3\times 10^{-6}Kg$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.