Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems: 68

Answer

$1.1 \times 10^{-2}N$

Work Step by Step

As explained in the text, in figure 10–34 there is both a top and a bottom surface. $$\gamma = \frac{F}{2 \mathcal{l}}$$ $$F=2 \gamma \mathcal{l}=2(0.025 N/m)(0.215m) =1.1 \times 10^{-2}N$$
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