Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems - Page 288: 57

Answer

$F=1100N$

Work Step by Step

$r_1=0.035m$ $r_2=0.00375m$ $\frac{V}{t}=Av$ $420\frac{L}{min}\times\frac{1m^3}{1000L}\times\frac{min}{60s}=0.007\frac{m^3}{s}$ $\frac{m}{t}=\frac{m}{V}\times\frac{V}{t}=1000\frac{kg}{m^3}\times0.007\frac{m^3}{s}=7.0\frac{kg}{s}$ $v_1=\frac{V}{tA_1}=1.82\frac{m}{s}$ $v_2=\frac{V}{tA_2}=1.58\times10^2\frac{m}{s}$ $F=ma=m\frac{v}{t}=7.0\frac{kg}{s}\times(v_2-v_1)=1100N$
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