Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems - Page 287: 31

Answer

The percent of the iceberg that is above the water surface is 10.5%

Work Step by Step

Let $V_i$ be the total volume of the iceberg. Let $V_w$ be the volume of the iceberg that is submerged in the water. Note that $V_w$ is the volume of water that is displaced. The buoyant force is equal to the weight of the iceberg. Therefore; $F_B = M_i~g$ $\rho_w~V_w~g = \rho_i~V_i~g$ $\frac{V_w}{V_i} = \frac{\rho_i}{\rho_w}$ $\frac{V_w}{V_i} = \frac{0.917 \times 10^3~kg/m^3}{1.025\times 10^3~kg/m^3}$ $\frac{V_w}{V_i} = 0.895 = 89.5\%$ The percent of the iceberg that is submerged is 89.5%. Therefore, the percent of the iceberg that is above the water surface is 10.5%.
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